Difference between revisions of "Assembly Language Logical Shift"
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==Multiplication example== | ==Multiplication example== | ||
− | This example uses a Logical Shift to perform multiplication. | + | This example uses a Logical Shift to perform multiplication. R2 is used to store the second value of the multiplication, and for every shift we subtract 2 from this. We then compare it with #1, because if it is greater we still need to do a shift, if it is less than we have finished the calculation. However if the comparison is equal, we need to finally add the first number to the total. |
− | + | MOV R0, #13 | |
− | + | MOV R1, #9 | |
MOV R2, R1 | MOV R2, R1 | ||
MOV R3, R0 | MOV R3, R0 | ||
Line 18: | Line 18: | ||
BLT END | BLT END | ||
ADD R3,R3,R0 | ADD R3,R3,R0 | ||
− | END: | + | END: HALT |
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Latest revision as of 12:20, 21 January 2020
Logical Shift Left
A Logical Shift Left will shift the binary pattern and add a zero at the least significant place value. For example the binary for 4 is '00100' a logical shift to the left of one place will give '01000' which is now 8. A logical shift to the left by one digit will multiply by 2. A logical shift of 2 places on '00100' will give '10000' which is 16, therefore a logical shift to the left by two digits will multiply by 4.
Logical Shift Right
A Logical Shift Right by a single digit will half the value, this essentially removes the least significant place value and shifts the other digits to the right. If the value represented is 13 ie '01101' a logical shift to the right of one place will remove the least significant place value so it will now be '00110' which is 6. 13 divided by 2 is 6 remainder 1. A logical shift to the right of two place will turn 13 '01101' into '00011' which is 3, ie 13 divided by 4 (the remainder will be 1).
Multiplication example
This example uses a Logical Shift to perform multiplication. R2 is used to store the second value of the multiplication, and for every shift we subtract 2 from this. We then compare it with #1, because if it is greater we still need to do a shift, if it is less than we have finished the calculation. However if the comparison is equal, we need to finally add the first number to the total.
MOV R0, #13 MOV R1, #9 MOV R2, R1 MOV R3, R0 LOOP: LSL R3,R3,#1 SUB R2,R2,#2 CMP R2,#1 BGT LOOP BLT END ADD R3,R3,R0 END: HALT